Version 19 DHS 3.2
Content: 3.2v19.pdf (53.72 KB)
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DHS - 3.2
№1.19. Vertices ∆АВС are given: А (3; –1); B (11; 3); C (–6; 2). Find: a) Equation side AB; b) Equation of height CH; c) the median AM equation; d) the intersection point N of the median AM and the height of the SN; e) the equation of a straight line passing through the vertex C and parallel to the side AB; e) distance from point C to straight line AB.
№2.19. Find the equation of the perpendiculars to the line 3x + 5y - 15 = 0, drawn through the intersection points of this line with the axes of coordinates.
№1.19. Vertices ∆АВС are given: А (3; –1); B (11; 3); C (–6; 2). Find: a) Equation side AB; b) Equation of height CH; c) the median AM equation; d) the intersection point N of the median AM and the height of the SN; e) the equation of a straight line passing through the vertex C and parallel to the side AB; e) distance from point C to straight line AB.
№2.19. Find the equation of the perpendiculars to the line 3x + 5y - 15 = 0, drawn through the intersection points of this line with the axes of coordinates.
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