45. Solving a chemistry problem
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5. EMF of the element in which the reaction proceeds reversibly
0.5Hg2CI2 Ag = AgCI Hg,
is 0.456 V at 298 K and 0.439 V at 293 K. Calculate ΔG, ΔH and ΔS of the reaction.
0.5Hg2CI2 Ag = AgCI Hg,
is 0.456 V at 298 K and 0.439 V at 293 K. Calculate ΔG, ΔH and ΔS of the reaction.
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