32. Solution to Chemistry Problem
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8. Calculate the reaction equation that allows hydrogen peroxide to decompose at standard temperature:
a) H2O2(l) = H2(g) O2 (g),
b) H2O2(l) = H2O(l) 0.5O2(g).
ΔН0f (Н202)(l) = - 187.9 kJ/mol S°(H202)(l) = 109.6 J/(mol*K)
S° (H2)(r) = 130.5 J/(mol*K)
ΔН0f (Н20)(l) = - 285.8 kJ/mol S° (02)(r) = 205.0 J/(mol*K)
S°(H20)(l) = 70.3 J/(mol*K)
a) H2O2(l) = H2(g) O2 (g),
b) H2O2(l) = H2O(l) 0.5O2(g).
ΔН0f (Н202)(l) = - 187.9 kJ/mol S°(H202)(l) = 109.6 J/(mol*K)
S° (H2)(r) = 130.5 J/(mol*K)
ΔН0f (Н20)(l) = - 285.8 kJ/mol S° (02)(r) = 205.0 J/(mol*K)
S°(H20)(l) = 70.3 J/(mol*K)
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