34. Solution to Chemistry Problem
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4. Calculate the enthalpy of formation of N2O5 (g) at 298 K, based on the following data:
2NO(g) O2(g)=2NO2(g) ΔH0298=-114.2 kJ
4NO2(g) O2(g)=2N2O5(g) ΔH0298=-110.2 kJ
N2(g) O2(g)=2NO(g) ΔH0298=182.6 kJ
2NO(g) O2(g)=2NO2(g) ΔH0298=-114.2 kJ
4NO2(g) O2(g)=2N2O5(g) ΔH0298=-110.2 kJ
N2(g) O2(g)=2NO(g) ΔH0298=182.6 kJ
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