34. Solution to Chemistry Problem
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9. Calculate the heat of reaction NH3 5/4O2=NO 3/2H2O(g) at T=298 K, if the following data are known:
H2O(g)=H2O(l) ΔH10=-44 kJ*mol-1
1/2N2 3/2H2=HNH3 ΔH20=-46.2 kJ*mol-1
H2 1/2O2=H2O(l) ΔH30=-285.8 kJ*mol-1
NO=1/2N2 1/2O2 ΔH40=-91.3 kJ*mol-1
H2O(g)=H2O(l) ΔH10=-44 kJ*mol-1
1/2N2 3/2H2=HNH3 ΔH20=-46.2 kJ*mol-1
H2 1/2O2=H2O(l) ΔH30=-285.8 kJ*mol-1
NO=1/2N2 1/2O2 ΔH40=-91.3 kJ*mol-1
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